given the function $h(x)=-x^{2}+7x + 18$, determine the average rate of change of the function over the…

given the function $h(x)=-x^{2}+7x + 18$, determine the average rate of change of the function over the interval $1leq xleq10$.
Answer
Explanation:
Step1: Recall average rate - of - change formula
The average rate of change of a function $y = h(x)$ over the interval $[a,b]$ is $\frac{h(b)-h(a)}{b - a}$. Here, $a = 1$, $b = 10$, and $h(x)=-x^{2}+7x + 18$.
Step2: Calculate $h(1)$
Substitute $x = 1$ into $h(x)$: $h(1)=-(1)^{2}+7(1)+18=-1 + 7+18=24$.
Step3: Calculate $h(10)$
Substitute $x = 10$ into $h(x)$: $h(10)=-(10)^{2}+7(10)+18=-100 + 70+18=-12$.
Step4: Calculate the average rate of change
Use the formula $\frac{h(10)-h(1)}{10 - 1}$. $\frac{h(10)-h(1)}{10 - 1}=\frac{-12 - 24}{9}=\frac{-36}{9}=-4$.
Answer:
$-4$