given the function h(x)=x² - 9x + 18, determine the average rate of change of the function over the interval…

given the function h(x)=x² - 9x + 18, determine the average rate of change of the function over the interval 4 ≤ x ≤ 11.
Answer
Explanation:
Step1: Recall average - rate - of - change formula
The average rate of change of a function $y = h(x)$ over the interval $[a,b]$ is $\frac{h(b)-h(a)}{b - a}$. Here, $a = 4$, $b = 11$, and $h(x)=x^{2}-9x + 18$.
Step2: Calculate $h(11)$
Substitute $x = 11$ into $h(x)$: $h(11)=11^{2}-9\times11 + 18=121-99 + 18=40$.
Step3: Calculate $h(4)$
Substitute $x = 4$ into $h(x)$: $h(4)=4^{2}-9\times4 + 18=16-36 + 18=-2$.
Step4: Calculate the average rate of change
$\frac{h(11)-h(4)}{11 - 4}=\frac{40-(-2)}{7}=\frac{42}{7}=6$.
Answer:
6