given the function below, fill in the table of values and use the table values to graph. \n$y = x - 1$\n|…

given the function below, fill in the table of values and use the table values to graph. \n$y = x - 1$\n| $x$ | $y = x - 1$ |\n| --- | --- |\n| $-3$ | |\n| $-2$ | |\n| $-1$ | |\n| $0$ | |\n| $1$ | |\n| $2$ | |\n| $3$ | |

given the function below, fill in the table of values and use the table values to graph. \n$y = x - 1$\n| $x$ | $y = x - 1$ |\n| --- | --- |\n| $-3$ | |\n| $-2$ | |\n| $-1$ | |\n| $0$ | |\n| $1$ | |\n| $2$ | |\n| $3$ | |

Answer

Explanation:

Step1: Substitute x = -3

Substitute ( x = -3 ) into ( y = x - 1 ). So ( y = -3 - 1 ).

Step2: Calculate the value

( -3 - 1 = -4 ). So when ( x = -3 ), ( y = -4 ). (We can continue for other x values: For ( x = -2 ): ( y = -2 - 1 = -3 ) For ( x = -1 ): ( y = -1 - 1 = -2 ) For ( x = 0 ): ( y = 0 - 1 = -1 ) For ( x = 1 ): ( y = 1 - 1 = 0 ) For ( x = 2 ): ( y = 2 - 1 = 1 ) For ( x = 3 ): ( y = 3 - 1 = 2 ) But the first blank (x=-3) is calculated as above.)

Answer:

For ( x = -3 ), the value of ( y ) is (-4). (And the complete table values are: when ( x=-3, y=-4 ); ( x=-2, y=-3 ); ( x=-1, y=-2 ); ( x=0, y=-1 ); ( x=1, y=0 ); ( x=2, y=1 ); ( x=3, y=2 ))