given the function below, fill in the table of values, use the table of values to graph the function, and…

given the function below, fill in the table of values, use the table of values to graph the function, and then identify the function’s domain and range. \n$y = \\left(\\frac{1}{2}\\right)^x - 1$\n| $x$ | $\\left(\\frac{1}{2}\\right)^x$ | $y = \\left(\\frac{1}{2}\\right)^x - 1$ |\n| --- | --- | --- |\n| $-3$ | | |\n| $-2$ | | |\n| $-1$ | | |\n| $0$ | | |\n| $1$ | | |\n| $2$ | | |

given the function below, fill in the table of values, use the table of values to graph the function, and then identify the function’s domain and range. \n$y = \\left(\\frac{1}{2}\\right)^x - 1$\n| $x$ | $\\left(\\frac{1}{2}\\right)^x$ | $y = \\left(\\frac{1}{2}\\right)^x - 1$ |\n| --- | --- | --- |\n| $-3$ | | |\n| $-2$ | | |\n| $-1$ | | |\n| $0$ | | |\n| $1$ | | |\n| $2$ | | |

Answer

Explanation:

Step1: Calculate $\left(\frac{1}{2}\right)^x$ for $x=-3$

$\left(\frac{1}{2}\right)^{-3} = 2^3 = 8$

Step2: Calculate $y$ for $x=-3$

$y = 8 - 1 = 7$

Step3: Calculate $\left(\frac{1}{2}\right)^x$ for $x=-2$

$\left(\frac{1}{2}\right)^{-2} = 2^2 = 4$

Step4: Calculate $y$ for $x=-2$

$y = 4 - 1 = 3$

Step5: Calculate $\left(\frac{1}{2}\right)^x$ for $x=-1$

$\left(\frac{1}{2}\right)^{-1} = 2^1 = 2$

Step6: Calculate $y$ for $x=-1$

$y = 2 - 1 = 1$

Step7: Calculate $\left(\frac{1}{2}\right)^x$ for $x=0$

$\left(\frac{1}{2}\right)^0 = 1$

Step8: Calculate $y$ for $x=0$

$y = 1 - 1 = 0$

Step9: Calculate $\left(\frac{1}{2}\right)^x$ for $x=1$

$\left(\frac{1}{2}\right)^1 = \frac{1}{2}$

Step10: Calculate $y$ for $x=1$

$y = \frac{1}{2} - 1 = -\frac{1}{2}$

Step11: Calculate $\left(\frac{1}{2}\right)^x$ for $x=2$

$\left(\frac{1}{2}\right)^2 = \frac{1}{4}$

Step12: Calculate $y$ for $x=2$

$y = \frac{1}{4} - 1 = -\frac{3}{4}$

Step13: Identify domain of the function

Exponential functions accept all real numbers as inputs, so the domain is all real $x$.

Step14: Identify range of the function

$\left(\frac{1}{2}\right)^x > 0$ for all real $x$, so $\left(\frac{1}{2}\right)^x - 1 > -1$.

Answer:

Completed Table:

$x$ $\left(\frac{1}{2}\right)^x$ $y = \left(\frac{1}{2}\right)^x - 1$
$-3$ $8$ $7$
$-2$ $4$ $3$
$-1$ $2$ $1$
$0$ $1$ $0$
$1$ $\frac{1}{2}$ $-\frac{1}{2}$
$2$ $\frac{1}{4}$ $-\frac{3}{4}$

Domain and Range:

  • Domain: All real numbers, or $(-\infty, \infty)$
  • Range: All real numbers greater than $-1$, or $(-1, \infty)$