given: a. sin(x) b. cos(x) c. cos(y) d. sin(y) use the drop - down menus in the derivation of the cosine sum…

given: a. sin(x) b. cos(x) c. cos(y) d. sin(y) use the drop - down menus in the derivation of the cosine sum identity: sin(x + y)=cos(π/2-(x + y))=cos((π/2 - x)-y)=cos(π/2 - x)□+sin(π/2 - x)□=sin(x)cos(y)+cos(x)sin(y)
Answer
Explanation:
Step1: Recall cosine - difference identity
The cosine - difference identity is $\cos(A - B)=\cos A\cos B+\sin A\sin B$. Here $A=\frac{\pi}{2}-x$ and $B = y$. So $\cos((\frac{\pi}{2}-x)-y)=\cos(\frac{\pi}{2}-x)\cos y+\sin(\frac{\pi}{2}-x)\sin y$.
Step2: Use co - function identities
We know that $\cos(\frac{\pi}{2}-x)=\sin x$ and $\sin(\frac{\pi}{2}-x)=\cos x$. Substituting these into the above expression, we get $\sin x\cos y+\cos x\sin y$.
Answer:
The first blank should be filled with $\cos(y)$ and the second blank should be filled with $\sin(y)$. So the answers are C and D.