given that $f(x)=sqrt{x}$, which equation describes the graph of function $g$?\n$g(x)=-f(x)-1$\n$g(x)=-f(x)+1…

Explanation:

Step1: Analyze reflection

The graph of $y = f(-x)$ reflects the graph of $y = f(x)$ across the y - axis. The original function $f(x)=\sqrt{x}$ has a domain $x\geq0$, and the graph of $g(x)$ seems to be a reflection of $f(x)$ across the y - axis, which is consistent with $f(-x)$.

Step2: Analyze vertical shift

The graph of $g(x)$ is shifted down by 1 unit compared to the reflected graph. For a function $y = h(x)$, a vertical shift down by $k$ units is given by $y=h(x)-k$. Here $k = 1$, so the function is $f(-x)-1$.

Answer:

$g(x)=f(-x)-1$