graph the exponential function.\n\n$g(x)=-2(\\frac{1}{2})^x$\n\nplot five points on the graph of the…

Explanation:

Step1: Choose x - values

Let (x=- 2,-1,0,1,2).

Step2: Calculate y - values for (x = - 2)

Substitute (x=-2) into (g(x)=-2(\frac{1}{2})^{x}), we get (g(-2)=-2\times(\frac{1}{2})^{-2}=-2\times4 = - 8). The point is ((-2,-8)).

Step3: Calculate y - values for (x=-1)

Substitute (x = - 1) into (g(x)=-2(\frac{1}{2})^{x}), we get (g(-1)=-2\times(\frac{1}{2})^{-1}=-2\times2=-4). The point is ((-1,-4)).

Step4: Calculate y - values for (x = 0)

Substitute (x = 0) into (g(x)=-2(\frac{1}{2})^{x}), we get (g(0)=-2\times(\frac{1}{2})^{0}=-2\times1=-2). The point is ((0,-2)).

Step5: Calculate y - values for (x = 1)

Substitute (x = 1) into (g(x)=-2(\frac{1}{2})^{x}), we get (g(1)=-2\times\frac{1}{2}=-1). The point is ((1,-1)).

Step6: Calculate y - values for (x = 2)

Substitute (x = 2) into (g(x)=-2(\frac{1}{2})^{x}), we get (g(2)=-2\times(\frac{1}{2})^{2}=-2\times\frac{1}{4}=-\frac{1}{2}). The point is ((2,-\frac{1}{2})).

Answer:

The five points are ((-2,-8),(-1,-4),(0,-2),(1,-1),(2,-\frac{1}{2}))