graph the exponential function.\n\n$g(x)=-\frac{1}{2}(2)^{x}$\n\nplot five points on the graph of the…

graph the exponential function.\n\n$g(x)=-\frac{1}{2}(2)^{x}$\n\nplot five points on the graph of the function. then click on the graph - a - function button.

graph the exponential function.\n\n$g(x)=-\frac{1}{2}(2)^{x}$\n\nplot five points on the graph of the function. then click on the graph - a - function button.

Answer

Explanation:

Step1: Choose x - values

Let (x=- 2,-1,0,1,2).

Step2: Calculate (g(x)) for (x = - 2)

Substitute (x=-2) into (g(x)=-\frac{1}{2}(2)^{x}), we get (g(-2)=-\frac{1}{2}(2)^{-2}=-\frac{1}{2}\times\frac{1}{4}=-\frac{1}{8}).

Step3: Calculate (g(x)) for (x=-1)

Substitute (x = - 1) into (g(x)), (g(-1)=-\frac{1}{2}(2)^{-1}=-\frac{1}{2}\times\frac{1}{2}=-\frac{1}{4}).

Step4: Calculate (g(x)) for (x = 0)

Substitute (x = 0) into (g(x)), (g(0)=-\frac{1}{2}(2)^{0}=-\frac{1}{2}\times1=-\frac{1}{2}).

Step5: Calculate (g(x)) for (x = 1)

Substitute (x = 1) into (g(x)), (g(1)=-\frac{1}{2}(2)^{1}=-1).

Step6: Calculate (g(x)) for (x = 2)

Substitute (x = 2) into (g(x)), (g(2)=-\frac{1}{2}(2)^{2}=-\frac{1}{2}\times4=-2).

The five points are ((-2,-\frac{1}{8}),(-1,-\frac{1}{4}),(0,-\frac{1}{2}),(1, - 1),(2,-2))

Answer:

The five points are ((-2,-\frac{1}{8}),(-1,-\frac{1}{4}),(0,-\frac{1}{2}),(1, - 1),(2,-2))