the graph of y = f(x) has the following features: f(-1)=2, lim(x→ - 1⁻)f(x)=0, lim(x→ - 1⁺)f(x)=1. which of…

Explanation:

Step1: Analyze (f(-1) = 2)

The function value at (x=-1) is 2, so the graph must have a point ((-1,2)).

Step2: Analyze (\lim_{x\rightarrow - 1^{-}}f(x)=0)

As (x) approaches - 1 from the left - hand side, the function approaches 0. So the left - hand limit at (x = - 1) is 0.

Step3: Analyze (\lim_{x\rightarrow - 1^{+}}f(x)=1)

As (x) approaches - 1 from the right - hand side, the function approaches 1. So the right - hand limit at (x=-1) is 1. We look for a graph that has a point at ((-1,2)), the curve approaching 0 as (x) approaches - 1 from the left and approaching 1 as (x) approaches - 1 from the right.

Answer:

We need to visually inspect the given graphs to find the one that satisfies the above - mentioned conditions. Without the ability to directly view and select from the provided graphs, we can't give a specific graph identifier. But the correct graph should have a solid dot at the point ((-1,2)), the curve approaching (y = 0) as (x) approaches - 1 from the left and approaching (y = 1) as (x) approaches - 1 from the right. If there is a graph among the options that meets these criteria, that is the answer. If none of them do, the answer is "None of these".