the graph of the following function has one relative extreme point. find it and determine whether it is a…

the graph of the following function has one relative extreme point. find it and determine whether it is a relative maximum or a relative minimum.\nf(x)=6x^{2}-5x - 1\nthe relative extreme point is \n(type an ordered pair. simplify your answer. use integers or fractions for any numbers in the expression.)
Answer
Explanation:
Step1: Find the derivative
The derivative of $f(x)=6x^{2}-5x - 1$ using the power - rule $(x^n)'=nx^{n - 1}$ is $f'(x)=12x-5$.
Step2: Set the derivative equal to zero
Set $f'(x) = 0$, so $12x-5=0$. Solving for $x$ gives $x=\frac{5}{12}$.
Step3: Find the second - derivative
The second - derivative $f''(x)$ of $f'(x)=12x - 5$ is $f''(x)=12$. Since $f''(\frac{5}{12})=12>0$, the function has a relative minimum at $x = \frac{5}{12}$.
Step4: Find the $y$ - value
Substitute $x=\frac{5}{12}$ into the original function $f(x)=6x^{2}-5x - 1$. [ \begin{align*} f(\frac{5}{12})&=6\times(\frac{5}{12})^{2}-5\times\frac{5}{12}-1\ &=6\times\frac{25}{144}-\frac{25}{12}-1\ &=\frac{25}{24}-\frac{50}{24}-\frac{24}{24}\ &=\frac{25 - 50-24}{24}\ &=-\frac{49}{24} \end{align*} ]
Answer:
$(\frac{5}{12},-\frac{49}{24})$