graph the following and state the range and all vertical asymptotes in equation form. show work…

graph the following and state the range and all vertical asymptotes in equation form. show work! f(x)=cot(1/2(x + π))+3 identify: (be careful of signs!) a= b= c= d= range = vertical asymptotes =

graph the following and state the range and all vertical asymptotes in equation form. show work! f(x)=cot(1/2(x + π))+3 identify: (be careful of signs!) a= b= c= d= range = vertical asymptotes =

Answer

Explanation:

Step1: Identify the general form parameters

The general form of the cotangent - function is $y = a\cot(b(x - c))+d$. For the function $f(x)=\cot(\frac{1}{2}(x + \pi))+3$, we have $a = 1$, $b=\frac{1}{2}$, $c=-\pi$, $d = 3$.

Step2: Find the range

The range of the basic cotangent function $y=\cot(x)$ is $(-\infty,\infty)$. A vertical shift of $d = 3$ units does not change the range. So the range of $y=\cot(\frac{1}{2}(x+\pi)) + 3$ is $(-\infty,\infty)$.

Step3: Find the vertical asymptotes

The vertical asymptotes of the basic cotangent function $y = \cot(x)$ occur at $x=n\pi$, where $n\in\mathbb{Z}$. For the function $y=\cot(b(x - c))+d$, the vertical - asymptotes are given by the equation $b(x - c)=n\pi$. Substitute $b=\frac{1}{2}$ and $c = -\pi$ into $b(x - c)=n\pi$: [ \begin{align*} \frac{1}{2}(x+\pi)&=n\pi\ x+\pi&=2n\pi\ x&=2n\pi-\pi=(2n - 1)\pi,n\in\mathbb{Z} \end{align*} ]

Answer:

$a = 1$, $b=\frac{1}{2}$, $c=-\pi$, $d = 3$ Range: $(-\infty,\infty)$ Vertical Asymptotes: $x=(2n - 1)\pi,n\in\mathbb{Z}$