which is the graph of $f(x) = \\frac{1}{4}(4)^x$?

Explanation:

Step1: Find y-intercept (x=0)

$f(0)=\frac{1}{4}(4)^0=\frac{1}{4}(1)=\frac{1}{4}$

Step2: Calculate f(1)

$f(1)=\frac{1}{4}(4)^1=\frac{1}{4}(4)=1$

Step3: Calculate f(2)

$f(2)=\frac{1}{4}(4)^2=\frac{1}{4}(16)=4$

Step4: Match points to graphs

The points $(0, \frac{1}{4})$, $(1,1)$, $(2,4)$ correspond to the top graph (first one), which has a y-intercept near 0, passes through (1,1) and (2,4), and increases as x increases.

Answer:

The top-most graph (the first one with points (1,1) and (2,4) on an increasing curve starting near the origin on the y-axis)