graph the function.\n$f(x)=\\begin{cases}x - 2&\\text{if }x < 1\\\\-5&\\text{if }x\\geq1\\end{cases}$
graph the function.\n$f(x)=\\begin{cases}x - 2&\\text{if }x < 1\\\\-5&\\text{if }x\\geq1\\end{cases}$
Answer
Explanation:
Step1: Analyze (y = x - 2) for (x<1)
When (x = 1), (y=1 - 2=-1). Since (x<1), the point ((1,-1)) is not included (open - circle at (x = 1) for this part of the function). The slope of (y=x - 2) is (m = 1) and the (y) - intercept is (b=-2).
Step2: Analyze (y=-5) for (x\geq1)
When (x = 1), (y=-5). So there is a closed - circle at the point ((1,-5)) for this part of the function. The function (y =-5) is a horizontal line.
Answer:
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