graph the function.\n$y = \\frac{1}{2}x^{3}$\nplot five points on the graph of the function: one point with…

graph the function.\n$y = \\frac{1}{2}x^{3}$\nplot five points on the graph of the function: one point with $x = 0$, two points with negative $x$-values, and two points with positive $x$-values. then click on the graph - a - function button.

graph the function.\n$y = \\frac{1}{2}x^{3}$\nplot five points on the graph of the function: one point with $x = 0$, two points with negative $x$-values, and two points with positive $x$-values. then click on the graph - a - function button.

Answer

Explanation:

Step1: Find point when x = 0

Substitute (x = 0) into (y=\frac{1}{2}x^{3}). Then (y=\frac{1}{2}\times0^{3}=0). The point is ((0,0)).

Step2: Find a negative - x point

Let (x=-2). Then (y=\frac{1}{2}\times(-2)^{3}=\frac{1}{2}\times(-8)= - 4). The point is ((-2,-4)).

Step3: Find another negative - x point

Let (x = - 4). Then (y=\frac{1}{2}\times(-4)^{3}=\frac{1}{2}\times(-64)=-32). The point is ((-4,-32)).

Step4: Find a positive - x point

Let (x = 2). Then (y=\frac{1}{2}\times2^{3}=\frac{1}{2}\times8 = 4). The point is ((2,4)).

Step5: Find another positive - x point

Let (x = 4). Then (y=\frac{1}{2}\times4^{3}=\frac{1}{2}\times64 = 32). The point is ((4,32)).

Answer:

The five points are ((0,0)), ((-2,-4)), ((-4,-32)), ((2,4)), ((4,32))