how does the graph of $y = \\sec(x - 2)+2$ compare to the graph of $y = \\sec(x)$?\nit is shifted 2 units…

Explanation:

Step1: Analyze horizontal shift

For a function $y = f(x - h)+k$, the horizontal shift is determined by $h$. In $y=\sec(x - 2)+2$, since $h = 2$, the graph of $y=\sec(x)$ is shifted 2 units to the right.

Step2: Analyze vertical shift

The vertical shift is determined by $k$. Here $k = 2$, so the graph of $y=\sec(x)$ is shifted 2 units up.

Answer:

It is shifted 2 units up and 2 units right.