the graph shows $f(x) = \\left(\\frac{1}{2}\\right)^x$ and its translation, $g(x)$. which describes the…

the graph shows $f(x) = \\left(\\frac{1}{2}\\right)^x$ and its translation, $g(x)$. which describes the translation of $f(x)$ to $g(x)$? \\bigcirc translation of four units up \\bigcirc translation of five units up \\bigcirc translation of four units to the right \\bigcirc translation of five units to the right
Answer
Explanation:
Step1: Analyze the y-intercepts
For ( f(x)=\left(\frac{1}{2}\right)^x ), when ( x = 0 ), ( f(0)=\left(\frac{1}{2}\right)^0=1 ). So the y - intercept of ( f(x) ) is ( (0,1) ). For ( g(x) ), from the graph, when ( x = 0 ), ( g(0) = 5 ).
Step2: Determine the vertical translation
The general form of a vertical translation of a function ( y = f(x) ) is ( y=f(x)+k ), where ( k>0 ) means a translation of ( k ) units up. We know that ( f(0) = 1 ) and ( g(0)=5 ). Let ( g(x)=f(x)+k ). Substituting ( x = 0 ), we get ( g(0)=f(0)+k ), so ( 5 = 1 + k ), which gives ( k = 4 ). Wait, no, wait. Wait, maybe I made a mistake. Wait, let's check the points. Wait, another way: look at the horizontal or vertical shift. Wait, the blue graph is ( f(x) ), red is ( g(x) ). At ( x = 0 ), ( f(0)=1 ), ( g(0)=5 ). The difference in the y - values is ( 5 - 1=4 )? No, wait, no, wait the graph: Wait, the blue curve (f(x)) has y - intercept at (0,1), the red curve (g(x)) has y - intercept at (0,5)? Wait, no, the red curve at x = 0 is at y = 5? Wait, no, looking at the graph, the red curve (g(x)) at x = 0 is at y = 5? Wait, the blue curve (f(x)) at x = 0 is at y = 1. So the vertical distance between the two y - intercepts is ( 5 - 1 = 4 )? Wait, no, wait the options: translation of four units up, five units up, etc. Wait, maybe I misread the y - intercept. Wait, let's re - examine. The blue graph (f(x)): when x = 0, y = 1. The red graph (g(x)): when x = 0, y = 5? Wait, no, the red graph at x = 0 is at y = 5? Wait, the grid: the y - axis has marks. The blue graph passes through (0,1), the red graph passes through (0,5). So the vertical shift: from y = 1 to y = 5 is a shift of 4 units up? Wait, no, 5 - 1=4? Wait, but the options have translation of four units up or five units up. Wait, maybe I made a mistake. Wait, let's check the function again. Wait, ( f(x)=\left(\frac{1}{2}\right)^x ), when x=- 2, ( f(-2)=\left(\frac{1}{2}\right)^{-2}=4 ). The blue graph at x=-2 is at y = 4. The red graph at x=-2: let's see, the red graph at x=-2, what's its y - value? From the graph, the red graph at x=-2 is at y = 8? Wait, no, the blue graph at x=-2 is y = 4, the red graph at x=-2 is y = 8? Wait, no, the blue curve (f(x)): when x=-2, ( f(-2)=\left(\frac{1}{2}\right)^{-2}=4 ), which matches the blue dot at x=-2, y = 4. The red curve (g(x)) at x=-2: the red dot at x=-2 is at y = 8? Wait, 8 - 4 = 4? No, 8 - 4 = 4? Wait, no, 8-4 = 4? Wait, no, if f(-2)=4, and g(-2)=8, then g(x)=f(x)+4? But at x = 0, f(0)=1, g(0)=5, 5 - 1 = 4. So the vertical shift is 4 units up? But wait, the options: translation of four units up, five units up. Wait, maybe I made a mistake. Wait, let's check the problem again. The function ( f(x)=\left(\frac{1}{2}\right)^x ), and its translation g(x). The key is to see the vertical shift. The y - intercept of f(x) is (0,1), the y - intercept of g(x) is (0,5). The difference is 5 - 1 = 4? Wait, no, 5 - 1 is 4? Wait, 1+4 = 5. So the translation is 4 units up. Wait, but let's check the options. The first option is translation of four units up.
Wait, but wait, maybe I messed up horizontal and vertical. Wait, if it's a horizontal shift, the form is ( g(x)=f(x - h) ). Let's check a point. For f(x), when x=-2, f(-2)=4. For g(x), when x=-2, what's g(-2)? From the graph, the red dot at x=-2 is at y = 8? Wait, no, the blue dot at x=-2 is y = 4, red dot at x=-2 is y = 8? Wait, f(-2)=4, g(-2)=8. If g(x)=f(x)+k, then 8 = 4 + k, k = 4. So vertical shift of 4 units up. So the answer should be translation of four units up.
Answer:
translation of four units up