a group of chickasaw nation members are playing a game called chunkey. to play, player 1 rolls a stone disk…

a group of chickasaw nation members are playing a game called chunkey. to play, player 1 rolls a stone disk while player 2 throws a pole to the location where they think the disk will stop rolling. player 2 receives a point if the pole touches the stone.\nthe table shows values from a quadratic function, $h(t)$, that models the elevation, in feet, of a players pole $t$ seconds after it has been thrown. what is the average rate of change in the poles elevation over the interval $0.5, 1.25$?\n| time after being thrown in seconds $t$ | 0 | 0.25 | 0.5 | 0.75 | 1 | 1.25 |\n| elevation in feet $h(t)$ | 5.5 | 8.6 | 9.8 | 8.9 | 6 | 1.1 |\nchunkey pole elevation

a group of chickasaw nation members are playing a game called chunkey. to play, player 1 rolls a stone disk while player 2 throws a pole to the location where they think the disk will stop rolling. player 2 receives a point if the pole touches the stone.\nthe table shows values from a quadratic function, $h(t)$, that models the elevation, in feet, of a players pole $t$ seconds after it has been thrown. what is the average rate of change in the poles elevation over the interval $0.5, 1.25$?\n| time after being thrown in seconds $t$ | 0 | 0.25 | 0.5 | 0.75 | 1 | 1.25 |\n| elevation in feet $h(t)$ | 5.5 | 8.6 | 9.8 | 8.9 | 6 | 1.1 |\nchunkey pole elevation

Answer

Explanation:

Step1: Recall average rate - of - change formula

The average rate of change of a function $y = f(x)$ over the interval $[a,b]$ is $\frac{f(b)-f(a)}{b - a}$. Here, $a = 0.5$, $b=1.25$, $f(t)=H(t)$. So the average rate of change is $\frac{H(1.25)-H(0.5)}{1.25 - 0.5}$.

Step2: Find $H(1.25)$ and $H(0.5)$ from the table

From the table, $H(1.25)=1.1$ and $H(0.5)=9.8$.

Step3: Substitute values into the formula

$\frac{H(1.25)-H(0.5)}{1.25 - 0.5}=\frac{1.1 - 9.8}{1.25-0.5}=\frac{- 8.7}{0.75}=-11.6$.

Answer:

$-11.6$