the height, h, of a falling object t seconds after it is dropped from a platform 300 feet above the ground…

the height, h, of a falling object t seconds after it is dropped from a platform 300 feet above the ground is modeled by the function h(t)=300 - 16t². which expression could be used to determine the average rate at which the object falls during the first 3 seconds of its fall?\no h(3)-h(0)\no h(\\frac{3}{3})-h(\\frac{0}{3})\no \\frac{h(3)}{3}\no \\frac{h(3)-h(0)}{3}

the height, h, of a falling object t seconds after it is dropped from a platform 300 feet above the ground is modeled by the function h(t)=300 - 16t². which expression could be used to determine the average rate at which the object falls during the first 3 seconds of its fall?\no h(3)-h(0)\no h(\\frac{3}{3})-h(\\frac{0}{3})\no \\frac{h(3)}{3}\no \\frac{h(3)-h(0)}{3}

Answer

Answer:

D. $\frac{h(3)-h(0)}{3}$

Explanation:

Step1: Recall average - rate formula

The average rate of change of a function $y = f(x)$ over the interval $[a,b]$ is given by $\frac{f(b)-f(a)}{b - a}$.

Step2: Identify variables for the height - function

For the height function $h(t)=300 - 16t^{2}$, we want to find the average rate of change over the interval $[0,3]$. Here, $a = 0$, $b = 3$, and $f(t)=h(t)$.

Step3: Substitute values into the formula

Substituting $a = 0$, $b = 3$ into the average - rate formula $\frac{f(b)-f(a)}{b - a}$, we get $\frac{h(3)-h(0)}{3-0}=\frac{h(3)-h(0)}{3}$.