what is the horizontal asymptote of f(x) = 3^x?\no y = 1\no y = 2\no y = 0\no y = 5

Explanation:

Step1: Recall exponential - function property

For an exponential function of the form $y = a^x$ where $a>1$ (here $a = 3$), as $x\to-\infty$, $y\to0$. As $x\to+\infty$, $y\to+\infty$. The horizontal - asymptote is determined by the behavior of the function as $x\to\pm\infty$. The general form of a horizontal asymptote is $y = k$, where $k$ is a constant value that the function approaches as $x\to\pm\infty$. For $y = 3^x$, as $x\to-\infty$, $3^x=\frac{1}{3^{-x}}\to0$.

Answer:

$y = 0$