hw 11 - chain rule section 2.6 (1 point) let $f(x)=\frac{1}{(x^{5}-4x + 7)^{8}}$. find $f(x)$. $f(x)=square$
hw 11 - chain rule section 2.6 (1 point) let $f(x)=\frac{1}{(x^{5}-4x + 7)^{8}}$. find $f(x)$. $f(x)=square$
Answer
Answer:
(-\frac{8(5x^{4}-4)}{(x^{5}-4x + 7)^{9}})