identify the asymptotes.\n\n$w(x)=\\frac{x + 7}{x^{2}+4x - 12}$\n\npart: $0/3$\n\npart 1 of 3\n\nequation(s)…

identify the asymptotes.\n\n$w(x)=\\frac{x + 7}{x^{2}+4x - 12}$\n\npart: $0/3$\n\npart 1 of 3\n\nequation(s) of vertical asymptote(s):

identify the asymptotes.\n\n$w(x)=\\frac{x + 7}{x^{2}+4x - 12}$\n\npart: $0/3$\n\npart 1 of 3\n\nequation(s) of vertical asymptote(s):

Answer

Explanation:

Step1: Factor the denominator

Factor (x^{2}+4x - 12). We look for two numbers that multiply to (-12) and add up to (4). The numbers are (6) and (-2). So, (x^{2}+4x - 12=(x + 6)(x-2)).

Step2: Find the vertical asymptotes

Set the factored denominator equal to zero ((x + 6)(x - 2)=0). Using the zero - product property (x+6 = 0) gives (x=-6) and (x - 2=0) gives (x = 2).

Answer:

(x=-6), (x = 2)