identify the coordinates of any local and absolute extreme points and inflection points. graph the…

identify the coordinates of any local and absolute extreme points and inflection points. graph the function.\n\n$y = 12x^{3}-x^{4}=x^{3}(12 - x)$\n\nidentify the coordinates of the absolute minimum points. select the correct choice below and,\nif necessary, fill in the answer box to complete your choice.\n\na. the absolute minimum point(s) is/are\n(use a comma to separate answers as needed. type an ordered pair. do not use commas in\nthe individual coordinates.)\n\nb. there are no absolute minimum points.\n\nidentify the coordinates of any inflection points. select the correct choice below and, if necessary, fill\nin the answer box to complete your choice.\n\na. the inflection point(s) is/are\n(use a comma to separate answers as needed. type an ordered pair. do not use commas in\nthe individual coordinates.)\n\nb. there are no inflection points.
Answer
Explanation:
Step1: Find the first derivative
Use the power rule ((x^n)^\prime = nx^{n - 1}). For (y = 12x^3-x^4), (y^\prime=36x^2 - 4x^3=4x^2(9 - x))
Step2: Find the second derivative
Differentiate (y^\prime = 36x^2-4x^3) using the power rule. (y^{\prime\prime}=72x-12x^2 = 12x(6 - x))
Step3: Find inflection points
Set (y^{\prime\prime}=0), so (12x(6 - x)=0) Solving (12x(6 - x)=0) gives (x = 0) or (x = 6) When (x = 0), (y=12\times0^3-0^4 = 0) When (x = 6), (y=12\times6^3-6^4=12\times216 - 1296=2592-1296 = 1296)
Answer:
A. The inflection point(s) is/are ((0,0),(6,1296))