identify the discontinuous functions and arrange them according to the positions of their points of infinite…

identify the discontinuous functions and arrange them according to the positions of their points of infinite discontinuity on the coordinate plane, from the farthest left to the farthest right. f(x)=(x² + 2x - 63)/(x + 7) g(x)=(x² - 2x - 35)/(x - 5) h(x)=(x²+6x - 55)/(x - 11) i(x)=(x² - 11x - 42)/(x + 4) j(x)=(x² + 4x)/(x - 2) k(x)=(x² - 3x - 54)/(x - 9) l(x)=(x² + 8x + 12)/(x² + 2) m(x)=(x² - 4x - 96)/(x - 8)

identify the discontinuous functions and arrange them according to the positions of their points of infinite discontinuity on the coordinate plane, from the farthest left to the farthest right. f(x)=(x² + 2x - 63)/(x + 7) g(x)=(x² - 2x - 35)/(x - 5) h(x)=(x²+6x - 55)/(x - 11) i(x)=(x² - 11x - 42)/(x + 4) j(x)=(x² + 4x)/(x - 2) k(x)=(x² - 3x - 54)/(x - 9) l(x)=(x² + 8x + 12)/(x² + 2) m(x)=(x² - 4x - 96)/(x - 8)

Answer

Explanation:

Step1: Find points of infinite - discontinuity

For a rational function $y = \frac{p(x)}{q(x)}$, points of infinite discontinuity occur where $q(x)=0$. For $f(x)=\frac{x^{2}+2x - 63}{x + 7}$, set $x+7 = 0$, then $x=-7$. For $g(x)=\frac{x^{2}-2x - 35}{x - 5}$, set $x - 5=0$, then $x = 5$. For $h(x)=\frac{x^{2}+6x - 55}{x - 11}$, set $x - 11=0$, then $x = 11$. For $i(x)=\frac{x^{2}-11x - 42}{x + 4}$, set $x + 4=0$, then $x=-4$. For $j(x)=\frac{x^{2}+4x}{x - 2}$, set $x - 2=0$, then $x = 2$. For $k(x)=\frac{x^{2}-3x - 54}{x - 9}$, set $x - 9=0$, then $x = 9$. For $l(x)=\frac{x^{2}+8x + 12}{x^{2}+2}$, since $x^{2}+2>0$ for all real $x$, there are no points of infinite - discontinuity. For $m(x)=\frac{x^{2}-4x - 96}{x - 8}$, set $x - 8=0$, then $x = 8$.

Step2: Arrange the points

The points of infinite discontinuity are $x=-7,x=-4,x = 2,x = 5,x = 8,x = 9,x = 11$. Arranging from the farthest left to the farthest right: $f(x),i(x),j(x),g(x),m(x),k(x),h(x)$

Answer:

$f(x),i(x),j(x),g(x),m(x),k(x),h(x)$