identify the horizontal asymptote of each graph.\n\no y = 0\no y = 1\no y = 6\ndone

Explanation:

Step1: Recall exponential - function property

For an exponential function of the form $y = a\cdot b^{x}+k$ ($a\neq0$, $b > 0$, $b\neq1$), when $a>0$ and $b > 1$ as in $t(x)=6^{x}$ (where $a = 1$, $b = 6$, $k = 0$), we consider the limit as $x\to-\infty$.

Step2: Calculate the limit

We know that $\lim_{x\to-\infty}6^{x}=\lim_{x\to-\infty}\frac{1}{6^{-x}}$. As $x\to-\infty$, $-x\to+\infty$, and $\lim_{x\to-\infty}\frac{1}{6^{-x}} = 0$.

Answer:

$y = 0$