identify the open intervals on which the function is increasing or decreasing. (enter your answers using…

identify the open intervals on which the function is increasing or decreasing. (enter your answers using interval notation.)\n$f(x)=\\sin(x)+6$ $0 < x < 2\\pi$\nincreasing\n\ndecreasing\n

identify the open intervals on which the function is increasing or decreasing. (enter your answers using interval notation.)\n$f(x)=\\sin(x)+6$ $0 < x < 2\\pi$\nincreasing\n\ndecreasing\n

Answer

Explanation:

Step1: Find the derivative of the function

The derivative of (y = f(x)=\sin(x)+6) is (f^\prime(x)=\cos(x)) (using the derivative rule ((\sin x)^\prime=\cos x) and ((C)^\prime = 0) for a constant (C)).

Step2: Determine where (f^\prime(x)>0) (increasing)

Set (\cos(x)>0). For (0 < x<2\pi), (\cos(x)>0) when (0 < x<\frac{\pi}{2}) and (\frac{3\pi}{2}<x < 2\pi). In interval notation, the function is increasing on (\left(0,\frac{\pi}{2}\right)\cup\left(\frac{3\pi}{2},2\pi\right)).

Step3: Determine where (f^\prime(x)<0) (decreasing)

Set (\cos(x)<0). For (0 < x<2\pi), (\cos(x)<0) when (\frac{\pi}{2}<x<\frac{3\pi}{2}). In interval notation, the function is decreasing on (\left(\frac{\pi}{2},\frac{3\pi}{2}\right)).

Answer:

Increasing: (\left(0,\frac{\pi}{2}\right)\cup\left(\frac{3\pi}{2},2\pi\right)) Decreasing: (\left(\frac{\pi}{2},\frac{3\pi}{2}\right))