identify the vertical asymptote of the function.\nf(x)=\frac{x^{2}+1}{3(x - 8)}\nthe vertical asymptote is…

identify the vertical asymptote of the function.\nf(x)=\frac{x^{2}+1}{3(x - 8)}\nthe vertical asymptote is at (x=)\ndone

identify the vertical asymptote of the function.\nf(x)=\frac{x^{2}+1}{3(x - 8)}\nthe vertical asymptote is at (x=)\ndone

Answer

Explanation:

Step1: Recall vertical - asymptote rule

Vertical asymptotes occur where the denominator of a rational function is zero and the numerator is non - zero. Set the denominator equal to zero: $3(x - 8)=0$.

Step2: Solve the equation for $x$

Divide both sides of the equation $3(x - 8)=0$ by 3: $x - 8=0$. Then add 8 to both sides: $x=8$. Check the numerator at $x = 8$: $8^{2}+1=64 + 1=65\neq0$.

Answer:

$8$