instructions - 1. find the difference quotient for the function $p(x)=3x - 2$. 2. find the difference…

instructions - 1. find the difference quotient for the function $p(x)=3x - 2$. 2. find the difference quotient for the function $m(x)=x^{2}+4x - 1$.
Answer
Explanation:
Step1: Recall the difference - quotient formula
The difference - quotient formula for a function $y = f(x)$ is $\frac{f(x + h)-f(x)}{h}$, where $h\neq0$.
Step2: Find the difference - quotient for $p(x)=3x - 2$
First, find $p(x + h)$: $p(x + h)=3(x + h)-2=3x+3h - 2$. Then, calculate $\frac{p(x + h)-p(x)}{h}$: [ \begin{align*} \frac{p(x + h)-p(x)}{h}&=\frac{(3x + 3h-2)-(3x - 2)}{h}\ &=\frac{3x+3h - 2-3x + 2}{h}\ &=\frac{3h}{h}\ &=3 \end{align*} ]
Step3: Find the difference - quotient for $m(x)=x^{2}+4x - 1$
First, find $m(x + h)$: $m(x + h)=(x + h)^{2}+4(x + h)-1=x^{2}+2xh+h^{2}+4x + 4h-1$. Then, calculate $\frac{m(x + h)-m(x)}{h}$: [ \begin{align*} \frac{m(x + h)-m(x)}{h}&=\frac{(x^{2}+2xh+h^{2}+4x + 4h-1)-(x^{2}+4x - 1)}{h}\ &=\frac{x^{2}+2xh+h^{2}+4x + 4h-1-x^{2}-4x + 1}{h}\ &=\frac{2xh+h^{2}+4h}{h}\ &=2x + h+4 \end{align*} ]
Answer:
- The difference - quotient for $p(x)$ is 3.
- The difference - quotient for $m(x)$ is $2x + h+4$.