(1) $\\int 1 - x ^ { 2 } d x =$

(1) $\\int 1 - x ^ { 2 } d x =$
Answer
Explanation:
Step1: Use integral formula
$$\int 1dx-\int x^{2}dx$$
Step2: Integrate term - by - term
$$\int 1dx=x+C_1,\int x^{2}dx=\frac{x^{3}}{3}+C_2$$
Step3: Combine results
$$x-\frac{x^{3}}{3}+C$$ ($C = C_1 - C_2$ is the constant of integration)
Answer:
$$x-\frac{x^{3}}{3}+C$$