6. $int -37e^{x}dx=\frac{-37e^{x + 1}}{x + 1}+c$ \no true \no false

Explanation:

Step1: Recall integral formula

The integral of $e^x$ with respect to $x$ is $\int e^x dx=e^x + C$. When we have $\int - 37e^x dx$, we can take out the constant - 37, so $\int - 37e^x dx=-37\int e^x dx$.

Step2: Calculate the integral

Since $\int e^x dx = e^x + C$, then $-37\int e^x dx=-37e^x + C$. And $\frac{-37e^{x + 1}}{x + 1}+C$ is not equal to $-37e^x + C$.

Answer:

False