introduction to the graphs of sine and cosine\nactivity 2\nlaunch:\nfill out the tables below:\nθ -2π -3π/2…

introduction to the graphs of sine and cosine\nactivity 2\nlaunch:\nfill out the tables below:\nθ -2π -3π/2 -π -π/2 0 π/2 π 3π/2 2π\n-sin θ\n \n \n \n \n0\n \n \n \n \nθ -2π -3π/2 -π -π/2 0 π/2 π 3π/2 2π\n-cos θ\n \n \n \n \n-1\n \n \n \n

introduction to the graphs of sine and cosine\nactivity 2\nlaunch:\nfill out the tables below:\nθ -2π -3π/2 -π -π/2 0 π/2 π 3π/2 2π\n-sin θ\n \n \n \n \n0\n \n \n \n \nθ -2π -3π/2 -π -π/2 0 π/2 π 3π/2 2π\n-cos θ\n \n \n \n \n-1\n \n \n \n

Answer

Explanation:

Step1: Recall sine - function values

Use the property of the sine function (y = \sin\theta). We know that (\sin(-2\pi)=0), (\sin(-\frac{3\pi}{2}) = 1), (\sin(-\pi)=0), (\sin(-\frac{\pi}{2})=- 1), (\sin(0) = 0), (\sin(\frac{\pi}{2})=1), (\sin(\pi)=0), (\sin(\frac{3\pi}{2})=-1), (\sin(2\pi)=0). Then for (y =-\sin\theta), we just change the sign of these values.

Step2: Recall cosine - function values

Use the property of the cosine function (y=\cos\theta). We know that (\cos(-2\pi)=1), (\cos(-\frac{3\pi}{2}) = 0), (\cos(-\pi)=-1), (\cos(-\frac{\pi}{2})=0), (\cos(0) = 1), (\cos(\frac{\pi}{2})=0), (\cos(\pi)=-1), (\cos(\frac{3\pi}{2})=0), (\cos(2\pi)=1). Then for (y =-\cos\theta), we just change the sign of these values.

Answer:

(\theta) (-2\pi) (-\frac{3\pi}{2}) (-\pi) (-\frac{\pi}{2}) (0) (\frac{\pi}{2}) (\pi) (\frac{3\pi}{2}) (2\pi)
(-\sin\theta) (0) (- 1) (0) (1) (0) (-1) (0) (1) (0)
(\theta) (-2\pi) (-\frac{3\pi}{2}) (-\pi) (-\frac{\pi}{2}) (0) (\frac{\pi}{2}) (\pi) (\frac{3\pi}{2}) (2\pi)
(-\cos\theta) (-1) (0) (1) (0) (-1) (0) (1) (0) (-1)