let g(x)=7x² - 8. (a) find the average rate of change from - 5 to 7. (b) find an equation of the secant line…

let g(x)=7x² - 8. (a) find the average rate of change from - 5 to 7. (b) find an equation of the secant line containing (-5, g(-5)) and (7, g(7)). (a) the average rate of change from - 5 to 7 is . (simplify your answer.)
Answer
Explanation:
Step1: Recall average - rate - of - change formula
The average rate of change of a function $y = g(x)$ from $x = a$ to $x = b$ is $\frac{g(b)-g(a)}{b - a}$. Here, $a=-5$, $b = 7$, and $g(x)=7x^{2}-8$.
Step2: Calculate $g(-5)$
Substitute $x=-5$ into $g(x)$: $g(-5)=7\times(-5)^{2}-8=7\times25 - 8=175-8 = 167$.
Step3: Calculate $g(7)$
Substitute $x = 7$ into $g(x)$: $g(7)=7\times7^{2}-8=7\times49-8=343 - 8=335$.
Step4: Calculate the average rate of change
$\frac{g(7)-g(-5)}{7-(-5)}=\frac{335 - 167}{7 + 5}=\frac{168}{12}=14$.
Answer:
14