let (f(x)=sin(pisqrt{\frac{x}{2}})) and (g(x)=-\frac{4}{21}cdot x(x - \frac{10}{3})). let (r) and (s) be the…

let (f(x)=sin(pisqrt{\frac{x}{2}})) and (g(x)=-\frac{4}{21}cdot x(x - \frac{10}{3})). let (r) and (s) be the two regions enclosed by the graphs of (f) and (g) as shown in the graph. find the sum of the areas of regions (r) and (s). use a graphing calculator and round your answer to three decimal places.
Answer
Explanation:
Step1: Recall area - between - curves formula
The area between two curves $y = f(x)$ and $y = g(x)$ from $x=a$ to $x = b$ is given by $A=\int_{a}^{b}|f(x)-g(x)|dx$. To find the sum of the areas of regions $R$ and $S$, we need to integrate $|f(x)-g(x)|$ over the interval from $x = 0$ to $x=4.5$.
Step2: Set up the integral
We have $A=\int_{0}^{4.5}\left|\sin\left(\pi\sqrt{\frac{x}{2}}\right)-\left(-\frac{4}{21}x\left(x - \frac{10}{3}\right)\right)\right|dx=\int_{0}^{4.5}\left|\sin\left(\pi\sqrt{\frac{x}{2}}\right)+\frac{4}{21}x\left(x - \frac{10}{3}\right)\right|dx$. First, expand $\frac{4}{21}x\left(x-\frac{10}{3}\right)=\frac{4}{21}x^{2}-\frac{40}{63}x$.
Step3: Use a graphing - calculator
Using a graphing calculator (such as TI - 84 Plus: enter $Y_1=\sin(\pi\sqrt{\frac{X}{2}})$ and $Y_2 =-\frac{4}{21}X*(X - \frac{10}{3})$, then use the integral function $\int_{0}^{4.5}|Y_1 - Y_2|dX$). The value of the integral $\int_{0}^{4.5}\left|\sin\left(\pi\sqrt{\frac{x}{2}}\right)+\frac{4}{21}x^{2}-\frac{40}{63}x\right|dx\approx 3.133$.
Answer:
$3.133$