let f(x) = (sqrt(x) - 3)/(sqrt(x) + 3). then, f(x) = (3x^(3/2))/((x^2 + 3)^2) f(5) =

let f(x) = (sqrt(x) - 3)/(sqrt(x) + 3). then, f(x) = (3x^(3/2))/((x^2 + 3)^2) f(5) =
Answer
Explanation:
Step1: Substitute x = 5 into f'(x)
Given (f'(x)=\frac{3x^{\frac{3}{2}}}{(x + 3)^2}), substitute (x = 5).
Step2: Calculate the numerator
The numerator is (3\times5^{\frac{3}{2}}=3\times5\times\sqrt{5}=15\sqrt{5}).
Step3: Calculate the denominator
The denominator is ((5 + 3)^2=64).
Answer:
(\frac{15\sqrt{5}}{64})