level 3: fill in the table.\n| $f(x)=x$ | $f(x)=-x^{2}$ | $(-\\infty,0)$ | none | $(0,0)$ |\n| $f(x)=x^{2}$…

level 3: fill in the table.\n| $f(x)=x$ | $f(x)=-x^{2}$ | $(-\\infty,0)$ | none | $(0,0)$ |\n| $f(x)=x^{2}$ | $(-\\infty,\\infty)$ | $f(x)=-x$ | $(0,\\infty)$ |\n| function | graph | concave up | concave down | inflection point |

level 3: fill in the table.\n| $f(x)=x$ | $f(x)=-x^{2}$ | $(-\\infty,0)$ | none | $(0,0)$ |\n| $f(x)=x^{2}$ | $(-\\infty,\\infty)$ | $f(x)=-x$ | $(0,\\infty)$ |\n| function | graph | concave up | concave down | inflection point |

Answer

Explanation:

Step1: Analyze $f(x)=-x^{2}$

The second - derivative $f''(x)=-2<0$ for all $x$. So it is concave down on $(-\infty,\infty)$ and has no concave - up interval and no inflection point.

Step2: Analyze $f(x)=x^{2}$

The second - derivative $f''(x) = 2>0$ for all $x$. So it is concave up on $(-\infty,\infty)$ and has no concave - down interval and no inflection point.

Step3: Analyze $f(x)=-x$

The first - derivative $f'(x)=-1$ and the second - derivative $f''(x)=0$. It is a straight line, so it is neither concave up nor concave down and has no inflection point.

Step4: Analyze $f(x)=x$

The first - derivative $f'(x)=1$ and the second - derivative $f''(x)=0$. It is a straight line, so it is neither concave up nor concave down and has no inflection point.

Answer:

Function Graph Concave up Concave down Inflection point
$f(x)=-x^{2}$ Parabola opening downwards None $(-\infty,\infty)$ None
$f(x)=x^{2}$ Parabola opening upwards $(-\infty,\infty)$ None None
$f(x)=-x$ Straight line with negative slope None None None
$f(x)=x$ Straight line with positive slope None None None