7 (b) lim(x→0) (sin x² / sin² x)
7 (b) lim(x→0) (sin x² / sin² x)
Answer
Explanation:
Step1: Use equivalent - infinitesimals
When (x\to0), (\sin u\sim u). So when (x\to0), (\sin x^{2}\sim x^{2}) and (\sin x\sim x).
Step2: Substitute equivalent - infinitesimals
(\lim_{x\rightarrow0}\frac{\sin x^{2}}{\sin^{2}x}=\lim_{x\rightarrow0}\frac{x^{2}}{x^{2}})
Answer:
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