what is the limit? lim x→−3 √x²−8 1 √−14 −5 √2

Explanation:

Step1: Substitute x value

Substitute (x = - 3) into (x^{2}-8). So we get ((-3)^{2}-8).

Step2: Calculate the value inside square - root

((-3)^{2}-8=9 - 8=1).

Step3: Find the square - root

(\lim_{x\rightarrow - 3}\sqrt{x^{2}-8}=\sqrt{1}=1).

Answer:

1