what is the limit? lim x→−3 √(x² - 8) 1 √(-14) -5 √2

Explanation:

Step1: Substitute x value

Substitute $x = - 3$ into $x^{2}-8$. So we get $(-3)^{2}-8$.

Step2: Calculate expression value

$(-3)^{2}-8=9 - 8=1$.

Step3: Find square - root

$\lim_{x\rightarrow - 3}\sqrt{x^{2}-8}=\sqrt{(-3)^{2}-8}=\sqrt{1}=1$.

Answer:

1