what is the limit? lim x→5 (√(x + 4) - 3)/(x - 5) 0 dne 1/6 -1/6

what is the limit? lim x→5 (√(x + 4) - 3)/(x - 5) 0 dne 1/6 -1/6
Answer
Explanation:
Step1: Rationalize the numerator
Multiply by $\frac{\sqrt{x + 4}+3}{\sqrt{x + 4}+3}$. $\lim_{x\rightarrow5}\frac{\sqrt{x + 4}-3}{x - 5}\times\frac{\sqrt{x + 4}+3}{\sqrt{x + 4}+3}=\lim_{x\rightarrow5}\frac{(x + 4)-9}{(x - 5)(\sqrt{x + 4}+3)}$
Step2: Simplify the numerator
$(x + 4)-9=x - 5$. $\lim_{x\rightarrow5}\frac{x - 5}{(x - 5)(\sqrt{x + 4}+3)}$
Step3: Cancel out common factors
Cancel out $x - 5$. $\lim_{x\rightarrow5}\frac{1}{\sqrt{x + 4}+3}$
Step4: Substitute $x = 5$
$\frac{1}{\sqrt{5+4}+3}=\frac{1}{3 + 3}=\frac{1}{6}$
Answer:
C. $\frac{1}{6}$