o y = ln x o y = ln x + 1 o y = e^x o y = e^x + 1

Explanation:

Step1: Analyze key - points of the graph

The graph passes through the point $(0, 1)$.

Step2: Check each function

For $y = \ln x$, when $x = 0$, $\ln x$ is undefined. For $y=\ln x + 1$, when $x = 0$, $\ln x$ is undefined. For $y = e^{x}$, when $x = 0$, $y=e^{0}=1$. For $y = e^{x}+1$, when $x = 0$, $y=e^{0}+1=2$.

Answer:

$y = e^{x}$