o y = e^x+5\no y = e^x+4\no y = ln x+4\no y = ln x+5
o y = e^x+5\no y = e^x+4\no y = ln x+4\no y = ln x+5
Answer
Explanation:
Step1: Analyze domain
The graph exists for all real - valued (x). The domain of (y = \ln x) is (x>0), so we can rule out the functions with (\ln x) (i.e., (y=\ln x + 4) and (y=\ln x+5)) since the graph has points for (x\leq0).
Step2: Analyze y - intercept
The y - intercept of a function (y = f(x)) is found by setting (x = 0). For (y=e^{x}+5), when (x = 0), (y=e^{0}+5=1 + 5=6). For (y=e^{x}+4), when (x = 0), (y=e^{0}+4=1 + 4=5). Looking at the graph, the y - intercept is around (y = 5).
Answer:
(y = e^{x}+4)