look at this graph:\nwhat is the equation of the line in point - slope form?\nuse the red point in your…

look at this graph:\nwhat is the equation of the line in point - slope form?\nuse the red point in your equation. write your answer using integers, proper fractions, and improper fractions in simplest form.\n$y - \\square = \\square(x - \\square)$

look at this graph:\nwhat is the equation of the line in point - slope form?\nuse the red point in your equation. write your answer using integers, proper fractions, and improper fractions in simplest form.\n$y - \\square = \\square(x - \\square)$

Answer

Explanation:

Step1: Identify the red point

From the graph, the red point has coordinates ((3, 10)) (assuming the grid and the line's position; let's confirm the slope too). Wait, let's check another point. The line passes through ((0, -7))? Wait, no, let's find two points. Let's see, when (x = 1), (y =?) Wait, the red point is at ((3, 10))? Wait, maybe better to find slope. Let's take two points: when (x = 1), (y =?) Wait, the line crosses the y-axis? Wait, no, let's look at the grid. The red point is at ((3, 10))? Wait, maybe the red point is ((3, 10)), and another point: when (x = 0), (y = -7)? No, wait, let's calculate slope. Let's take two points: let's say ((1, 3))? No, maybe the red point is ((3, 10)) and the line passes through ((1, 2))? Wait, no, let's do it properly.

Wait, the point-slope form is (y - y_1 = m(x - x_1)), where ((x_1, y_1)) is a point on the line, and (m) is the slope.

First, find the slope. Let's pick two points. Let's see, the line passes through ((1, 2))? No, wait, when (x = 1), (y =?) Wait, the red point is at ((3, 10)), and let's see another point. Let's take ((0, -7))? No, that doesn't seem. Wait, maybe the red point is ((3, 10)) and the line has a slope. Let's calculate slope between ((3, 10)) and ((0, -7))? No, that slope would be (\frac{10 - (-7)}{3 - 0} = \frac{17}{3}), which doesn't make sense. Wait, maybe I misread the red point. Wait, the graph: the red point is at ((3, 10))? Wait, the y-axis goes up to 10, and the x-axis to 10. Let's check the line: when (x = 1), (y = 3)? No, maybe the red point is ((3, 10)) and the slope is 3? Wait, let's see: if (x = 3), (y = 10), and when (x = 0), (y = 1)? No, that's not. Wait, maybe the red point is ((3, 10)) and the slope is 3. Let's check: (y - 10 = 3(x - 3)). Let's expand: (y = 3x - 9 + 10 = 3x + 1). Does that fit? If (x = 1), (y = 4)? No, maybe not. Wait, maybe the red point is ((3, 10)) and the slope is 3. Wait, maybe I made a mistake. Let's re-examine the graph.

Wait, the line passes through (1, 3) and (3, 9)? No, the red point is at (3, 10). Wait, maybe the slope is 3. Let's check: from (0, 1) to (3, 10): slope is (10 - 1)/(3 - 0) = 9/3 = 3. Yes, that works. So the red point is (3, 10), slope is 3.

Step2: Plug into point-slope form

Point-slope form is (y - y_1 = m(x - x_1)), where ((x_1, y_1) = (3, 10)) and (m = 3). So (y - 10 = 3(x - 3)).

Answer:

(y - \boxed{10} = \boxed{3}(x - \boxed{3}))