what is the maximum of f(x) = sin(x)?\n-2π\n-1\n1\n2π

Answer:

C. 1

Explanation:

Step1: Recall sine - function range

The range of the sine function $y = \sin(x)$ is $[-1,1]$. That is, $- 1\leqslant\sin(x)\leqslant1$ for all real - valued $x$.

Step2: Determine the maximum

From the range $[-1,1]$, the maximum value of $\sin(x)$ is 1.