what is the maximum of $f(x)=sin(x)$?\n- $-2pi$\n- $-1$\n- $1$\n- $2pi$
what is the maximum of $f(x)=sin(x)$?\n- $-2pi$\n- $-1$\n- $1$\n- $2pi$
Answer
Explanation:
Step1: Recall sine - function range
The range of the sine function $y = \sin(x)$ is $[- 1,1]$.
Step2: Identify maximum value
The maximum value within the range $[-1,1]$ is $1$.
Answer:
C. 1