1. what is the minimum value of the function f(x)=√(x - 4)+2? a 0 b 2 c 4 d 8

Explanation:

Step1: Analyze square - root property

The square - root function $\sqrt{x - 4}$ has the property that $\sqrt{x - 4}\geq0$ for all real $x$ in its domain ($x\geq4$).

Step2: Find minimum of the function

To find the minimum of $y = f(x)=\sqrt{x - 4}+2$, since the minimum value of $\sqrt{x - 4}$ is 0 (when $x = 4$), then the minimum value of $y$ is $0 + 2=2$.

Answer:

B. 2