a model train is launched from a toy train station with an initial velocity of 240 cm/s. the distance of the…

a model train is launched from a toy train station with an initial velocity of 240 cm/s. the distance of the train, d(t), after t seconds, can be modeled by the function d(t)=-12t² + 240t. the table below gives several values of this function. complete each of the 4 activities for this task. seconds distance from station 0 0 2 432 4 768 6 1008 8 1152 10 1200 12 1152 14 1008 16 768 18 432 20 0 what is the average rate of change, in centimeters per second, of the distance traveled between 4 seconds and 10 seconds? enter your numerical answer in the box below.

a model train is launched from a toy train station with an initial velocity of 240 cm/s. the distance of the train, d(t), after t seconds, can be modeled by the function d(t)=-12t² + 240t. the table below gives several values of this function. complete each of the 4 activities for this task. seconds distance from station 0 0 2 432 4 768 6 1008 8 1152 10 1200 12 1152 14 1008 16 768 18 432 20 0 what is the average rate of change, in centimeters per second, of the distance traveled between 4 seconds and 10 seconds? enter your numerical answer in the box below.

Answer

Explanation:

Step1: Identificar los valores de tiempo y distancia

Tomamos $t_1 = 4$, $d(t_1)=768$, $t_2 = 10$ y $d(t_2)=1200$.

Step2: Aplicar la fórmula de tasa de cambio promedio

La fórmula de tasa de cambio promedio es $\frac{d(t_2)-d(t_1)}{t_2 - t_1}$. Sustituimos los valores: $\frac{1200 - 768}{10 - 4}$.

Step3: Realizar los cálculos

$\frac{1200 - 768}{10 - 4}=\frac{432}{6}=72$.

Answer:

72