the movement of the progress bar may be uneven because questions can be worth more or less (including zero)…

Explanation:

Step1: Recall the general form of sine - function

The general form of a sine function is $y = A\sin(Bx - C)+D$. For the function $y = 3\sin(2x)$, $A = 3$, $B = 2$, $C = 0$, and $D = 0$.

Step2: Determine the amplitude

The amplitude of the function $y = A\sin(Bx)$ is given by $|A|$. Here, $A = 3$, so the amplitude is $|3|=3$. This means the graph oscillates between $y=-3$ and $y = 3$.

Step3: Determine the period

The period of the function $y=\sin(Bx)$ is $T=\frac{2\pi}{|B|}$. Since $B = 2$, the period $T=\frac{2\pi}{2}=\pi$.

The graph of $y = 3\sin(2x)$ has an amplitude of 3 and a period of $\pi$. Looking at the options, the graph with an amplitude of 3 (oscillating between - 3 and 3) and a period of $\pi$ is the second - graph from the left.

Answer: The second graph from the left.