mth 261 module 1 exam (sec 1.1 - 1.8) - form 1-21-a (honorlock) started: apr 6 at 6:36pm quiz instructions…
mth 261 module 1 exam (sec 1.1 - 1.8) - form 1-21-a (honorlock) started: apr 6 at 6:36pm quiz instructions show instructions question 4 4 pts find the limit, if it exists. limx→4 x² - 1 / x + 1 edit view insert format tools table 12pt paragraph b i u a t²
Answer
Explanation:
Step1: Substitute x = 4
Since the function $\frac{x^{2}-1}{x + 1}$ is a rational - function and the denominator is non - zero when $x = 4$ (because when $x=4$, $x + 1=4 + 1=5\neq0$), we can directly substitute $x = 4$ into the function. $\frac{4^{2}-1}{4 + 1}$
Step2: Calculate the numerator and denominator
First, calculate the numerator: $4^{2}-1=16 - 1=15$. The denominator is $4 + 1 = 5$. $\frac{15}{5}$
Step3: Simplify the fraction
$\frac{15}{5}=3$
Answer:
3