the number of grams of a certain radioactive substance present at time t is given by the formula ( a =…

the number of grams of a certain radioactive substance present at time t is given by the formula ( a = 700e^{-0.004t} ), where t is the number of years. find the number of grams that are present at time ( t = 0 ) and at time ( t = 900 ).\nthe number of grams present at time ( t = 0 ) is\n(round to the nearest hundredth as needed.)

the number of grams of a certain radioactive substance present at time t is given by the formula ( a = 700e^{-0.004t} ), where t is the number of years. find the number of grams that are present at time ( t = 0 ) and at time ( t = 900 ).\nthe number of grams present at time ( t = 0 ) is\n(round to the nearest hundredth as needed.)

Answer

Explanation:

Step1: Substitute (t = 0) into the formula

Given (A=700e^{- 0.004t}), when (t = 0), we have (A = 700e^{-0.004\times0}). Since (a^0=1) for (a\neq0), and here (a = e), (e^{0}=1). So (A = 700\times1).

Step2: Calculate the value

(A=700)

Answer:

(700)