3 numeric 1 point on the interval 0 ≤ θ < 2π, give any solution of the equation sin θ + 1 = 0 4.71
3 numeric 1 point on the interval 0 ≤ θ < 2π, give any solution of the equation sin θ + 1 = 0 4.71
Answer
Explanation:
Step1: Isolate sine function
Subtract 1 from both sides of $\sin\theta + 1=0$. We get $\sin\theta=- 1$.
Step2: Find the solution in given interval
We know that $\sin\theta=-1$ when $\theta=\frac{3\pi}{2}$ in the interval $0\leq\theta < 2\pi$. And $\frac{3\pi}{2}\approx\frac{3\times3.14}{2}=4.71$.
Answer:
$4.71$