overall accuracy: 70% record: 6 score: 4 if h(x) = b(x)/v(x), then h(x) = (b(x)v(x)+v(x)b(x))/v(x)^2…

overall accuracy: 70% record: 6 score: 4 if h(x) = b(x)/v(x), then h(x) = (b(x)v(x)+v(x)b(x))/v(x)^2 (b(x)v(x)-v(x)b(x))/v(x)^2 b(x)/v(x) (v(x)b(x)-b(x)v(x))/v(x)^2 high score board: overall refresh you must have at least 100 to be on the board. # name record

overall accuracy: 70% record: 6 score: 4 if h(x) = b(x)/v(x), then h(x) = (b(x)v(x)+v(x)b(x))/v(x)^2 (b(x)v(x)-v(x)b(x))/v(x)^2 b(x)/v(x) (v(x)b(x)-b(x)v(x))/v(x)^2 high score board: overall refresh you must have at least 100 to be on the board. # name record

Answer

Explanation:

Step1: Recall quotient - rule

The quotient - rule for differentiation states that if $h(x)=\frac{b(x)}{v(x)}$ where $b(x)$ and $v(x)$ are differentiable functions and $v(x)\neq0$, then $h^{\prime}(x)=\frac{b^{\prime}(x)v(x)-v^{\prime}(x)b(x)}{[v(x)]^{2}}$.

Answer:

$\frac{b^{\prime}(x)v(x)-v^{\prime}(x)b(x)}{[v(x)]^{2}}$